Subject: RE: [xsl] problem with multiple xsl:sort elements From: kakridge@xxxxxxxxxxxxx Date: Wed, 7 Jan 2004 02:04:21 -0500 |
I really appreciate you explaining this in English for me. You have been a big help. Thanks, Kenny Akridge -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Josh Canfield Sent: Tuesday, January 06, 2004 2:53 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] problem with multiple xsl:sort elements Sure, I can try to explain it. Essentially it's a grouping problem (see http://www.jenitennison.com/xslt/grouping/muenchian.html). In your case you want to bring together all of the AccountLineItem nodes that have the same value for GLAccountNumber. Your summation is correct, we just grab each unique AccountLineItem/GLAccountNumber we encounter and the inner loop collects all the AccountLineItem nodes that match the GLAccountNumber. I may have never come up with this method on my own either, but that's why I read this list, it's a good place to learn new techniques. :) Breaking down the selection: select="AccountLineItem[GLAccountNumber[not(. = preceding::GLAccountNumber)]] In English: Select all AccountLineItem nodes which have a child GLAccountNumber node that is not equal to any preceding GLAccountNumber nodes. The preceding:: axis here would also grab GLAccountNumber nodes that are outside of AccountLIneItem nodes. In your case this doesn't matter, but to be more specific I probably should have written preceding::AccountLineItem/GLAccountNumber. While writing this I noticed that you don't need to select the AccountLineItem nodes in the outer loop, but just the GLAccountNumber nodes. That would change the select statement to: select="AccountLineItem/GLAccountNumber[not(. = preceding::AccountLineItem/GLAccountNumber)]" In English: select GLAccountNumber nodes that are children of AccountLineItem nodes, and are not equal to any preceding GLAccountNumber nodes that are children of AccountLineItem nodes. The references to GLAccountNumber in the loop would change to self::node() or . (dot). Changing the select statement isn't critical, but it might make it easier to follow what is being used. Enjoy, Josh -----Original Message----- From: kakridge@xxxxxxxxxxxxx [mailto:kakridge@xxxxxxxxxxxxx] Sent: Tuesday, January 06, 2004 6:21 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] problem with multiple xsl:sort elements Josh, it seems like this code loops over the first node of every different GLAccountNumber. Then, it looks like an inner loop of all nodes that match the node held in the outer loop. Is this correct? I would have never thought of this. I don't even really understand how it works. Can you explain this for me: <xsl:for-each select="AccountLineItem[GLAccountNumber[not(. = preceding::GLAccountNumber)]]"> Thanks. -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Josh Canfield Sent: Monday, January 05, 2004 9:34 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] problem with multiple xsl:sort elements Your problem is here: <xsl:if test="not(GLAccountNumber = following::GLAccountNumber)"> following::GLAccountNumber is returning the next GLAccountNumber in document order, not in the order that the for-each is iterating over the elements. One solution would be to group the AccountLineItem elements together by GLAccountNumber and then output the subtotal after processing each GLAccountNumber. <xsl:key name="account-by-number" match="/ArrayOfAccountLineItem/AccountLineItem" use="GLAccountNumber"/> <xsl:template match="ArrayOfAccountLineItem"> <!-- iterate over distinct account numbers --> <xsl:for-each select="AccountLineItem[GLAccountNumber[not(. = preceding::GLAccountNumber)]]"> <xsl:sort select="GLAccountNumber" data-type="text" order="ascending"/> <!-- iterate over all matching account numbers --> <xsl:for-each select="key('account-by-number', GLAccountNumber)"> <xsl:sort select="substring(SettleDate,1,10)" data-type="text" order="ascending"/> <xsl:sort select="LineItemID" data-type="number" order="ascending"/> <xsl:apply-templates select="."/> </xsl:for-each> <!-- Summary line, used to be in xsl:if in the AccountLineItem template--> <tr> <td colspan="11">   </td> </tr> <tr> <td colspan="4">   </td> <td colspan="2" class="fieldName" align="center"> Total by Object Code: </td> <td class="bottomFieldInfo" align="right"> <xsl:value-of select="format-number(sum(key('subTotal', GLAccountNumber)/Amount[. > 1]), '#.00')"/> </td> <td>   </td> <td class="bottomFieldInfo" align="right" style="padding-right:5px"> <xsl:value-of select="translate(format-number(sum(key('subTotal', GLAccountNumber)/Amount[. < 0]), '#.00'), '-', '')"/> </td> <td colspan="2">   </td> </tr> <tr> <td colspan="11">   </td> </tr> </xsl:for-each> </table> </xsl:template> <xsl:template match="AccountLineItem"> <tr> <td class="fieldInfo"> <xsl:value-of select="substring(LineItemName,1,35)"/> </td> <td class="fieldInfo"> <xsl:value-of select="position()"/> </td> <td class="fieldInfo"> <xsl:value-of select="GLAccountNumber"/> </td> <td class="fieldInfo"> <xsl:value-of select="substring(RegistrantFullName,1,19)"/> </td> <td class="fieldInfo"> <xsl:value-of select="concat(substring(SettleDate,6,2), '/', substring(SettleDate,9,2), '/', substring(SettleDate,1,4))"/> </td> <td align="right" class="fieldInfo"> <xsl:value-of select="LineItemID"/> </td> <td class="fieldInfo" align="right"> <xsl:choose> <xsl:when test="Amount > 0"> <xsl:value-of select="format-number(Amount, '#.00')"/> </xsl:when> <xsl:otherwise>   </xsl:otherwise> </xsl:choose> </td> <td>   </td> <td align="right" class="fieldInfo" style="padding-right: 5px;"> <xsl:choose> <xsl:when test="Amount < 0"> <xsl:value-of select="translate(format-number(Amount, '#.00'), '-', '')"/> </xsl:when> <xsl:otherwise>   </xsl:otherwise> </xsl:choose> </td> <td class="fieldInfo"> <xsl:value-of select="substring(PaymentType,1,12)"/> </td> <td class="fieldInfo"> <xsl:value-of select="substring(PaymentReference,1,15)"/> </td> </tr> </xsl:template> Hope this helps, Josh XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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