Subject: Re: [xsl] generate XHTML header without causing xmlns attributes in e.g. <table>? From: "Emmanuil Batsis (Manos)" <mbatsis@xxxxxxxxxxx> Date: Fri, 17 Oct 2003 16:53:29 +0300 |
Hi Jarkko,
I thought I had to declare the name space in the xsl:template line like this:
<xsl:template name="exparameters" match="EX_PARAMETERS"
xml:space="preserve" xmlns="http://www.w3.org/1999/xhtml" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<table border="1" cellpadding="3" cellspacing="0"
class="parameters" >
<thead> <tr> ...
Well, normally these kind of declarations are done in the stylesheet level.
Originally I did it the way you suggests: I have removed the xml namespace declaration in the template def. and tried this:
<xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
However I get that xmlns="" in my table anyway?
The funny part is, I have two <table> tags in the page which is generated, and it is only in the second one that gets the xmlns attribute - why is that?
The template declarations look like this (now):
<xsl:template name="query" match="QUERY">
And <xsl:template name="exparameters" match="EX_PARAMETERS" xml:space="preserve">
First table tag in generated xhtml looks like this <table class="querydef" cellspacing="0" cellpadding="3" border="1">
Second table tag looks like this <table xmlns="" class="parameters" cellspacing="0" cellpadding="3" border="1">
I have tried searching the web for answers, but I don't think I've used the right keywords - I haven't been able to find anything which could lead me towards a solution to this. I am a beginner, so it might be even the simplest thing I've missed - so any help will be appreciated.
Have a great weekend everyone, Flemming
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
-- Manos Batsis
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