Subject: Re: [xsl] Re: XPath 2.0: Problems with the two boolean constants true and false From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 9 Oct 2003 14:44:29 +0100 |
Hi Dimitre, > But if the Data Model were saying that 0 and 1 are not simply > "string representations" (note that I didn't use '0' and '1' in my > previous example but just 0 and 1 -- that is not the strins '0' and > '1') but that 0 and 1 are *the* two xs:boolean constants, > > then > > it would make difference as the result of evaluating a boolean > expression would be not a "representation" but a real (or native, or > genuine) boolean value. > > Isn't it natural for a type to have its own genuine values and not > only a "representation"? Of course. But that's what we have currently, isn't it? The result of the expression: true() and false() is a native xs:boolean value, false, not the string 'false'. Perhaps you're finding problems because: <xsl:value-of select="true() and false()" /> generates a text node whose string value is the result of converting the xs:boolean value false to a string (i.e. 'false')? Perhaps you would be better off using: <xsl:sequence select="true() and false()" /> which actually adds the xs:boolean value false to the result sequence. In other words, use a template along the lines of: <xsl:template name="And" match="test:*" as="xs:boolean"> <xsl:param name="arg1" as="xs:boolean"/> <xsl:param name="arg2" as="xs:boolean"/> <xsl:sequence select="$arg1 and $arg2"/> </xsl:template> Note that here the template is declared to have an xs:boolean value as its result; that declarations isn't completely necessary (it will still have an xs:boolean value as its result without it), but it's good practice. (Returning the actual xs:boolean value should also be more efficient since you're not having to create any nodes that way -- <xsl:value-of>, theoretically at least, creates a text node.) Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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