Subject: RE: [xsl] Problem with XSL and Namespace From: "Giovani Librelotto" <grl@xxxxxxxxxxxx> Date: Tue, 15 Oct 2002 17:50:15 +0100 |
Jeni and David, I'm sorry. The xmlns="http://www.topicmaps.org/xtm/1.0/" attribute is a mistake. I'll redefine my problem. I'm making a stylesheet for generate another stylesheet. I'm using Saxon 6.5.2. I want to create a root element in the XML document final (generated by the second stylesheet) with a namespace xmlns:xlink="http://www.w3.org/1999/xlink" like above: <root xmlns:xlink="http://www.w3.org/1999/xlink"> But, if I define in the "mother" stylesheet this <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias"> <xsl:namespace-alias stylesheet-prefix="axsl" result-prefix="xsl"/> <axsl:template match="/"> <root xmlns:xlink="http://www.w3.org/1999/xlink"> ... <node> <ref xlink:href="#products"/> </node> ... </root> </axsl:template> the result XSL in "son" stylesheet is: <axsl:stylesheet xmlns:axsl="http://www.w3.org/1999/XSL/Transform" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <axsl:template match="/"> <root> ... <node> <ref xlink:href="#products"/> </node> ... </root> </axsl:template> The namespace xmlns:xlink="http://www.w3.org/1999/xlink" was retired of "root" element and put in "stylesheet" element. Why? So, the final XML document generated is: <root> ... <node> <ref xlink:href="#products"/> </node> ... </root> How can I to generate this? <root xmlns:xlink="http://www.w3.org/1999/xlink"> ... <node> <ref xlink:href="#products"/> </node> ... </root> Thanks in advance, ------------------------------------ Giovani Rubert Librelotto Ph.D. Student Universidade do Minho Braga - Portugal grl@xxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Jeni Tennison > Sent: Tuesday, October 15, 2002 4:36 PM > To: Giovani Librelotto > Cc: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Problem with XSL and Namespace > > > Hi Giovani, > > > the result XSL in stylesheet "son" is: > > > > <xstm:stylesheet xmlns:axsl="http://www.w3.org/1999/XSL/Transform" > > xmlns:xlink="http://www.w3.org/1999/xlink" > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> > > > > <axsl:template match="/"> > > <root xmlns="http://www.topicmaps.org/xtm/1.0/"> > > > > And in the final XML document generated is: > > > > <root> > > .. > > </root> > > If so, then your processor is buggy. Given the stylesheet > that you have above, the <root> element that's generated in > the output should have two namespace nodes on it, one for xlink > (http://www.w3.org/1999/xlink) and one for the default > namespace (http://www.topicmaps.org/xtm/1.0/). In order to > retain those nodes when serialized, it should look like: > > <root xmlns="http://www.topicmaps.org/xtm/1.0" > xmlns:xlink="http://www.w3.org/1999/xlink"> > ... > </root> > > Which processor are you using? If you simplified your example > (which I guess you did, given that the prefix for the > stylesheet element hasn't been declared), perhaps you can > show us the actual 'son' stylesheet that you're using and we > can see whether there's something in it that would cause the > namespace nodes to disappear. > > Cheers, > > Jeni > > --- > Jeni Tennison > http://www.jenitennison.com/ > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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