Subject: Re: [xsl] Generating the xml: namespace from XSLT into a schema From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Sat, 20 Jul 2002 17:51:43 +0100 |
Hi Danny, > I have a stylesheet that builds a Schema. In this schema I need to > output the xml:lang attribute on some elements in this schema. My > stylesheet creates the schema import statement as well as creating > the xml:lang attributes at the right place. The problem is I don't > get a namespace declaration at the top of the schema which the IBM > quality checker and MSV complain about. The Namespaces in XML Rec. states: The namespace prefix, *unless it is xml* or xmlns, must have been declared in a namespace declaration attribute in either the start-tag of the element where the prefix is used or in an an ancestor element (i.e. an element in whose content the prefixed markup occurs). The prefix xml is by definition bound to the namespace name http://www.w3.org/XML/1998/namespace. http://www.w3.org/TR/REC-xml-names/#nsc-NSDeclared (my emphasis) So MSV and the IBM quality checker should not complain about the fact that the xml prefix has not been declared; they are buggy. Unfortunately, the only work-around around their bugginess in XSLT is to revert to disable-output-escaping to create the xs:schema element, which is very ugly and might not even work (it depends on how you're calling the transformation). There's no clean way to force the XSLT processor to output a namespace declaration for the XML namespace. What I recommend you do, therefore, is use your stylesheet as is, and either write a custom serialiser to add a namespace declaration for the XML namespace or do a bit of search-and-replace text processing on the output of the transformation to add the namespace declaration. Oh, and I recommend that you write bug reports to the MSV and SQC developers. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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