Subject: RE: [xsl] The longest node in a node set From: DPawson@xxxxxxxxxxx Date: Fri, 19 Jul 2002 11:20:45 +0100 |
Mike said: > In XPath 2.0, the way you do this is: > > max(for $n in $nodeset return string-length($n)) > > In Saxon 6.5.x, you can do it with an extension function: > > saxon:max($nodeset, saxon:expr('string-length(.)')) > > (Both of these give you the length of the longest node, not the node > itself) Is it just me, or does that seem to defeat the objective? I would want the node, not its length? Regards DaveP - NOTICE: The information contained in this email and any attachments is confidential and may be legally privileged. If you are not the intended recipient you are hereby notified that you must not use, disclose, distribute, copy, print or rely on this email's content. If you are not the intended recipient, please notify the sender immediately and then delete the email and any attachments from your system. RNIB has made strenuous efforts to ensure that emails and any attachments generated by its staff are free from viruses. However, it cannot accept any responsibility for any viruses which are transmitted. We therefore recommend you scan all attachments. Please note that the statements and views expressed in this email and any attachments are those of the author and do not necessarily represent those of RNIB. RNIB Registered Charity Number: 226227 Website: http://www.rnib.org.uk XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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