Subject: RE: [xsl] xsl:sort question From: Sripriya Venkataraman <Sripriya.Venkataraman@xxxxxxxxxxxxxxx> Date: Fri, 26 Apr 2002 11:23:14 -0700 |
It works. Thanks a lot Joerg. Thanks, Priya -----Original Message----- From: Joerg Heinicke [mailto:joerg.heinicke@xxxxxx] Sent: Friday, April 26, 2002 11:15 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] xsl:sort question Hello Priya, your approach is correct, but incomplete. When you sort for @WellName, then the nodes will be selected alphabetically. The second sort will only have an effect, if two nodes are equal in the first sort criteria. What you need: <xsl:sort select="substring(@WellName,1,1)"/> <xsl:sort select="substring(@WellName,2)" data-type="number"/> Regards, Joerg > I am not getting the above result with my XSL. What is the problem ? > <xsl:template match="ANALYSISRESULTS"> > <xsl:variable name="wells" select="//WELL"/> > <xsl:for-each select="$wells"> > <xsl:sort select="@WellName"/> > <xsl:sort select="substring(@WellName,2)" > data-type="number"/> > <xsl:for-each select="@*"> > <xsl:value-of select="."/> <xsl:value-of > select="$tab"/> > </xsl:for-each> > <xsl:value-of select="$newline"/> > </xsl:for-each> > </xsl:template> > > Thanks, > Priya > X 323 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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