Subject: [xsl] <xsl:sort> question. From: "Dung, Ming-tzung" <Ming-tzung_Dung@xxxxxxxxxxxxx> Date: Fri, 19 Apr 2002 10:54:24 -0600 |
The version 1 will work and the version 2 will not sort the data, even though I think that these two are logically equivalent. Please let me know what you think? Thanks in advance!! ------ **Version1 - output the sorted last name** <xsl:template match="/"> <xsl:for-each select="addressbook/address"> <xsl:sort select="name/last-name"/> <p> <xsl:value-of select="name/last-name"/> </p> </xsl:for-each> </xsl:template> **Version 2 - output the sorted last name** <xsl:template match="/addressbook/address"> <xsl:for-each select="."> <xsl:sort select="name/last-name"/> <p> <xsl:value-of select="name/last-name"/> </p> </xsl:for-each> </xsl:template> **Input xml data ----- <?xml version="1.0"?> <addressbook> <address> <name> <title>Mr.</title> <first-name>Chester Hasbrouck</first-name> <last-name>Frisby</last-name> </name> </address> <address> <name> <first-name>Harry</first-name> <last-name>Backstayge</last-name> </name> </address> <address> <name> <first-name>Mary</first-name> <last-name>McGoon</last-name> </name> </address> <address> <name> <title>Ms.</title> <first-name>Amanda</first-name> <last-name>Reckonwith</last-name> </name> </address> </addressbook> ----- Ming XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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