Subject: [xsl] re: general problem From: saodl@xxxxxxxx Date: Fri, 18 Jan 2002 08:52:00 -0800 (PST) |
i'm no javascript expert, but i'm using a piece of code like this to grab the current xml document for manipulation in a javascript function. var xmlDoc = document.XMLDocument; if (xmlDoc == null){ xmlDoc = navigator.XMLDocument; } hope that helps. siri ------andrew@xxxxxxxxxxxxxxxxxxxxxxx wrote------ Hi all, Imagine I have a set of nodes like this: <root> <a> <b> <c> <d> <e> </a> <a> <b> <c> <d> <e> </a> </root> I apply a stylesheet to the xml to output a table that displays certain elements of each <a> such as: <tr> <td>b , c, d</td> </tr> Say I want to include a button next to that row that, when clicked, opens a window displaying -all- the elements for that <a>. I can do this by calling a javascript function, passing the position of the <a> node as a parameter, and using the DOM to extract the information I want. However, this currently relies on me hard-coding the name of the xml file (xmlObj.load('xmlfile')) into the function, which then makes the stylesheet useless for all but one xmlfile. If you understand what Im asking ;) is there a better way of doing this? Thanks to anyone on my wavelength, apolgies to everyone else cheers andrew XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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