Subject: Re: [xsl] unique elements from different sourcefile From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 3 Jan 2002 16:01:42 +0000 |
Thomas Winkler asked: > all i want is getting all possible children of a specific element. > since the content model of some elements can be very complicated > (such as "head"), most xpath axis don't work. Ken's already produced an XSLT 1.0 answer. For interest, possible XSLT 2.0 solutions would be: Using the distinct-values() function: <xsl:value-of select="distinct-values(.//element-name/@name)" separator=", " /> If you wanted to do something further with the element-name elements, the xsl:for-each-group element would be more use: <xsl:for-each-group select=".//element-name" group-by="@name"> <xsl:value-of select="@name" /> <xsl:if test="position() != last()">, </xsl:if> </xsl:for-each-group> Although you could just use xsl:for-each with distinct-values() if you wanted: <xsl:for-each select="distinct-values(.//element-name/@name)"> <xsl:value-of select="." /> <xsl:if test="position() != last()">, </xsl:if> </xsl:for-each> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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