Subject: [xsl] unique elements from different sourcefile From: Thomas Winkler <t.winkler@xxxxxxxxxxx> Date: 03 Jan 2002 14:31:21 +0100 |
hi, i'm really having a hard time figuring this little problem. because of simplicity and performance i used the muench method for finding unique elements and whatever else i needed. but this one just doesn't work for me. maybe i'm just too desperate to solve it myself.... i have a xml represantation of a dtd, generated by norman walshs dtdparse script in a separate xml file. all i want is getting all possible children of a specific element. since the content model of some elements can be very complicated (such as "head"), most xpath axis don't work. i looked through the faq, but the methods with the following axis are not working either. maybe someone could help me through this little one. <dtd> <element name="head" content-type="element"> <content-model-expanded> <sequence-group> <or-group occurrence="*"> <element-name name="meta"/> <element-name name="link"/> <element-name name="object"/> </or-group> <or-group> <sequence-group> <element-name name="title"/> <or-group occurrence="*"> <element-nam name="meta"/> <element-name name="link"/> <element-name name="object"/> </or-group> <sequence-group occurrence="?"> <element-name name="base"/> <or-group occurrence="*"> <element-name name="meta"/> <element-name name="link"/> <element-name name="object"/> </or-group> </sequence-group> </sequence-group> <sequence-group> <element-name name="base"/> <or-group occurrence="*"> <element-name name="meta"/> <element-name name="link"/> <element-name name="object"/> </or-group> <sequence-group> <element-name name="title"/> <or-group occurrence="*"> <element-name name="meta"/> <element-name name="link"/> <element-name name="object"/> </or-group> </sequence-group> </sequence-group> </or-group> </sequence-group> </content-model-expanded> </element> </dtd> i think i have to use at least two for loops, because if i generate the ids in one for loop as usual (without document() function) the first ones are not always identical and the xsl:for-each and xsl:key are not at the same nodeset. do i first have to <xsl:for-each select="document($xsldtdfile)/dtd/element[@name=current()]/content-model-expanded"> and then <xsl:for-each select=".//element-name"> with <xsl:key name="uChilds" match=".//element-name" use="@name" /> ???? what do my xsl:key and xsl:for-each(s) have to look like. i tried many things, i just don't want to write here. thank you for your help. thomas winkler XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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