Subject: RE: another simple problem... From: "Nick-Lawson.org" <nick@xxxxxxxxxxxxxxx> Date: Tue, 17 Oct 2000 05:07:54 +0100 |
If you want $file to be the admin _node_: <xsl:variable name="file" select="."/> and if you want $file to be the "admin" _string_: <xsl:variable name="file" select="name()"/> Nick > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of B. DEXHEIMER > Sent: 16 October 2000 17:02 > To: xsl-list@xxxxxxxxxxxxxxxx > Subject: another simple problem... > > > Hi People ! > > I have the following piece of code : > > <xsl:variable name="file">out</xsl:variable> > ... > <xsl:template match="ADMIN"> > <xsl:variable name="file"> > /* what I want to do is : file <- "ADMIN", ie the xsl variable > "file" receives "ADMIN", the node matching > element, as a new value instead of "out" but I do not want to write > "ADMIN" explicitely... the new value must be referred dynamically to the > upper node mentionned in the match instruction*/ > </xsl:variable> > > How could I do that ? > > Thanx for your Help! > > BeNjamin. > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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