Subject: to extract the longest string. (fwd) From: "C.V. Radhakrishnan" <cvr@xxxxxxxxxxxxxxx> Date: Mon, 21 Aug 2000 12:28:16 +0530 (IST) |
Jeni Tennison While sending the following code you said <xsl:template match="row" mode="get-longest"> <xsl:variable name="current"> <xsl:for-each select="col"> <xsl:value-of select="@align" /> </xsl:for-each> </xsl:variable> <xsl:variable name="longest"> <xsl:apply-templates select="following-sibling::row[1]" mode="get-longest" /> </xsl:variable> <xsl:choose> <xsl:when test="string-length($longest) > string-length($current)"> <xsl:value-of select="$longest" /> </xsl:when> <xsl:otherwise><xsl:value-of select="$current" /></xsl:otherwise> </xsl:choose> " So in effect calling this template on the second row element returns the longest result from all the rest of the rows," Would you please explain to me how calling this template on the second row element returns the longest result from all "the rest of rows" and how the recursion is working in that place? Thanks Rajagopal XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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