Subject: Building a new tree From: Bovone Stefano <Stefano.Bovone@xxxxxxxx> Date: Tue, 13 Apr 1999 16:01:21 +0200 |
I have, for example, the following XML document:
<?xml version="1.0"?>
<document>
<common id="D1">
<p>First common part A</p>
<p>First common part b</p>
</common>
<common id="D2">
<title>SECOND COMMON PART</title>
</common>
<letter>
<doc>
<title> THE DOCUMENT </TITLE>
<p> generic text</p>
<insert_common ref="D1"/>
<p> generic text</p>
<insert_common ref="D2"/>
</doc>
</letter>
</document>
and I want using a XSL document to have:
<?xml version="1.0"?>
<doc>
<title> THE DOCUMENT </TITLE>
<p> generic text</p>
<p>First common part A</p>
<p>First common part b</p>
<p> generic text</p>
<title>SECOND COMMON PART</title>
</doc>
I thought to use:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http:/www.w3.org/TR/WD-xsl">
<xsl:template match="/">
<xsl:template select=".//letter"/>
</xsl:template>
<xsl:template match="letter">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="letter/* | letter//*">
<xsl:copy>
<xsl:apply-templates select="text() | @* | * | ./* | insert_common"/>
</xsl:copy>
</xsl:template>
<xsl:template match="insert_common">
<xsl:apply-templates select="id(@ref)/tag"/>
</xsl:template>
<xsl:template match="tag/*">
<xsl:copy>
<xsl:apply-templates select="text() | * | ./*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
but it doesn't work.
Have anybody any idea ?
Thanks. Bye.
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